(3x^2+5x+50)/(x-5)

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Solution for (3x^2+5x+50)/(x-5) equation: 


D( x )

x-5 = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x in (-oo:5) U (5:+oo)

(3*x^2+5*x+50)/(x-5) = 0

3*x^2+5*x+50 = 0

3*x^2+5*x+50 = 0

DELTA = 5^2-(3*4*50)

DELTA = -575

DELTA < 0

1 = 0

1/(x-5) = 0

x belongs to the empty set

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